Capacitively Coupled Charge Qubits: Difference between revisions

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Project started in the Fall of 2014, focusing on the operation of two or more charge qubits which are capacitively coupled.
This project started in the Fall of 2014, focusing on the operation of two or more charge qubits which are capacitively coupled.
==General Formulation==
==General Formulation==
[[Image:Detuning graph.png|thumb|Energy levels of the 2 qubit system as a function of both detunings.|300px]]
[[Image:Detuning graph.png|thumb|Energy levels of the 2 qubit system as a function of both detunings.|300px]]
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\end{matrix}\right)
\end{matrix}\right)
</math>
</math>
We will refer to $\epsilon_i$ and $\Delta_i$ as the \emph{detuning} and \emph{tunnel coupling} of qubit $i$, respectively.
We will refer to <math>\epsilon_i</math> and <math>\Delta_i</math> as the ''detuning'' and ''tunnel coupling'' of qubit <math>i</math>, respectively.


We can further write down the full Hamiltonian explicitly:
We can further write down the full Hamiltonian explicitly:
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</math>
</math>


where <math>g</math> is the capacitive coupling between the qubits.


==Sweet Spots==
==Sweet Spots==

Revision as of 21:29, 24 October 2014

This project started in the Fall of 2014, focusing on the operation of two or more charge qubits which are capacitively coupled.

General Formulation

Energy levels of the 2 qubit system as a function of both detunings.

For a single charge qubit, the Hamiltonian is

We will refer to and as the detuning and tunnel coupling of qubit , respectively.

We can further write down the full Hamiltonian explicitly:

where is the capacitive coupling between the qubits.

Sweet Spots

A major issue with charge qubits is that they are very susceptible to charge noise, which occurs when charge fluctuations outside the system induce undesired shifts in the parameters of the Hamiltonian. The goal of a sweet spot is to find a point in the parameter space where the energy levels are as invariant to the shifts as possible.

Invariance to Detuning Noise

The most dominant noise source is due to the shifts in the detuning. It is believed that the only point at which the first order dependence on the detunings disappears is at \epsilon_1 = \epsilon_2 = 0.


Rotations