|
Size: 2234
Comment:
|
Size: 3466
Comment:
|
| Deletions are marked like this. | Additions are marked like this. |
| Line 23: | Line 23: |
| ||all other parts||ME, Bay , Shelf #|| || |
||Twin Weights with string||ME, Bay A1 , Shelf #3|| || ||Small 5g Weight||ME, Bay A1 , Shelf #3||With Twin Weights|| || || || || || || || || || || || || |
| Line 27: | Line 30: |
| * N/A |
* Make sure the Atwood stand is Plum. * The Atwood stand is more then 2 meters tall and must be held at an angle within the elevator. |
| Line 32: | Line 35: |
| 1. List steps for setup then procedure. 1. ... |
1. Plum the Atwood Stand by adjusting the 3 leveling screws on the base. 1. With a step stool, set the string that holds the weights over the pulley. So that there is one weight on both sides of the Atwood Machine. 1. Make sure the small 5g weight is on the front main weight. 1. Connect a 9 volt battery to a momentary switch to operate the electromagnet that holds up the weight platform at the top of the Atwood Machine. 1. Test the electromagnet. Make sure that it releases the weight platform so the weight is free to fall. 1. Reset the weight platform by moving the front weight up to the top and raising the weight platform under the weight. The platform will lock into place, with a click. 1. Slide and Set the stopping platform so that there is one meter between the two platforms. (ie. One meter of free fall distance.) 1. With the table display and large DMM set for "Stop Watch", one can measure the time it takes for the weight to fall one meter. 1. Do this 3 or more times and take the average. |
| Line 41: | Line 52: |
| Before the extra weight is added to the front mass, the two masses are equal and therefore the tension in the string is equal to the weight of one mass. Thus, the net force on each block is zero and they remain stationary. Once a small amount of weight is added to the front block, the net amount of force on each block will be the weight of the added mass. The direction of the net forces will be different for each mass. The rear mass will move upward since the tension is greater than its weight. Likewise, the front mass will move downward since its total weight is greater than the upward tension. Since the added mass is small, the acceleration of the system will be small. | Before the extra weight is added to the front mass, the two masses are equal and therefore the tension in the string is equal to the weight of one mass. Thus, the net force on each hanging weight is zero and they remain stationary. Once a small amount of weight is added to the front block, the net amount of force on each block will be the weight of the added mass. The direction of the net forces will be different for each mass. The rear mass will move upward since the tension is greater than its weight. Likewise, the front mass will move downward since its total weight is greater than the upward tension. Since the added mass is small, the acceleration of the system will be small. |
[:PiraScheme#Mechanics: Table of Mechanics Demonstration] |
[:MEEquipmentList: List of Mechanics Equipment & Supplies] |
[:Demonstrations:Lecture Demonstrations] |
Atwood's machine, 1G10.40
Topic and Concept:
Newton's Second Law, [:Newtons2NDLaw#ForceMassAndAcceleration: 1G10. Force, Mass, and Acceleration]
Location:
Cabinet: [:MechanicsCabinet:Mechanic (ME)]
Floor Item
East Wall
attachment:LargeAtwood-14-400.jpg
Abstract:
Two equal masses are hung from a pulley. A small amount of mass is added to the hanging weight on the front side. A timer is used of measure the free fall time of the the front mass over a distance of one meter.
Equipment |
Location |
ID Number |
|
|
|
Atwood Machine |
ME, Bay , Shelf # |
|
Twin Weights with string |
ME, Bay A1 , Shelf #3 |
|
Small 5g Weight |
ME, Bay A1 , Shelf #3 |
With Twin Weights |
|
|
|
|
|
|
|
|
|
Important Setup Notes:
- Make sure the Atwood stand is Plum.
- The Atwood stand is more then 2 meters tall and must be held at an angle within the elevator.
Setup and Procedure:
- Plum the Atwood Stand by adjusting the 3 leveling screws on the base.
- With a step stool, set the string that holds the weights over the pulley. So that there is one weight on both sides of the Atwood Machine.
- Make sure the small 5g weight is on the front main weight.
- Connect a 9 volt battery to a momentary switch to operate the electromagnet that holds up the weight platform at the top of the Atwood Machine.
- Test the electromagnet. Make sure that it releases the weight platform so the weight is free to fall.
- Reset the weight platform by moving the front weight up to the top and raising the weight platform under the weight. The platform will lock into place, with a click.
- Slide and Set the stopping platform so that there is one meter between the two platforms. (ie. One meter of free fall distance.)
- With the table display and large DMM set for "Stop Watch", one can measure the time it takes for the weight to fall one meter.
- Do this 3 or more times and take the average.
Cautions, Warnings, or Safety Concerns:
- N/A
Discussion:
Before the extra weight is added to the front mass, the two masses are equal and therefore the tension in the string is equal to the weight of one mass. Thus, the net force on each hanging weight is zero and they remain stationary. Once a small amount of weight is added to the front block, the net amount of force on each block will be the weight of the added mass. The direction of the net forces will be different for each mass. The rear mass will move upward since the tension is greater than its weight. Likewise, the front mass will move downward since its total weight is greater than the upward tension. Since the added mass is small, the acceleration of the system will be small.
attachment: photo |
attachment: photo |
attachment: photo |
attachment: photo |
Videos:
[https://www.youtube.com/user/LectureDemostrations/videos?view=1 Lecture Demonstration's Youtube Channel]
References:
[http://en.wikipedia.org/wiki/Atwood_machine Atwood Machine - Wikipedia]
[:Instructional:Home]